Table of Contents
- 1 Which ring below left or right would you expect to be more easily nitrated explain your choice?
- 2 Which of the following is correct for the Mononitration of phenyl benzoate?
- 3 How do you know if its ortho or para?
- 4 Which molecule would you expect to undergo the fastest rate of electrophilic aromatic substitution?
- 5 What is the Colour of phenyl benzoate?
- 6 How is phenyl benzoate prepared from phenol?
- 7 Is aniline more reactive than benzene?
- 8 How can I nitrate an ester with mixed acid?
Which ring below left or right would you expect to be more easily nitrated explain your choice?
The catalysts and co-reagents serve to generate the strong electrophilic species needed to effect the initial step of the substitution. The specific electrophile believed to function in each type of reaction is listed in the right hand column.
Which of the following is correct for the Mononitration of phenyl benzoate?
Thus, we can conclude the nitration of phenyl benzoate yields 4-nitrophenyl benzoate. Hence, we can conclude that the correct option is B.
How do you know if its ortho or para?
If the relative yield of the ortho product and that of the para product are higher than that of the meta product, the substituent on the benzene ring in the monosubstituted benzene is called an ortho, para directing group. If the opposite is observed, the substituent is called a meta directing group.
Which is most readily nitrated?
Phenol is more easily nitrated than benzene.
Which phenyl ring of n Phenylbenzamide is more reactive in electrophilic aromatic substitution reactions?
The left handed phenyl ring is more activated than the right handed phenyl ring. Hence the electrophile would preferentially attack on the left handed phenyl ring.
Which molecule would you expect to undergo the fastest rate of electrophilic aromatic substitution?
Therefore, since phenol contains the most strongly-activated ring towards EAS, it participates fastest in EAS.
What is the Colour of phenyl benzoate?
Specifications
Acidity | 1mg KOH/g max. |
---|---|
Color | White |
Melting Point | 68.0°C to 70.0°C |
Boiling Point | 298.0°C to 299.0°C |
Assay Percent Range | 98.5\% min. (GC) |
How is phenyl benzoate prepared from phenol?
Phenyl benzoate is prepared by Schotten- Baumann method of benzoylation. In this method of benzoylation phenols are reacted with benzoyl chloride in presence of aqueous sodium hydroxide and the reaction mixture is shaken vigorously.
Why is the -NO2 group added in para position in nitration?
Therfore, we would expect that -NO2 group will be added in para position with respect to the ester group in the ring which is directly attached to O atom of ester. This is the major concern of the question. 2. Reaction Condition : Generally nitration of an aromatic compound is done by using Mixed acid (Conc. HNO3+Conc.
What is the reaction condition for nitration of aromatic compounds?
2. Reaction Condition : Generally nitration of an aromatic compound is done by using Mixed acid (Conc. HNO3+Conc. H2SO4). But think about what might happen in this case. Here the starting material of the reaction is an ester, which might undergo acid catalyzed hydrolysis to give rise to benzoic acid and phenol.
Is aniline more reactive than benzene?
On a general note yes! Aniline it’s extremely reactive when it is compared to benzene because of the NH2 presence. Even in the absence of a catalyst it activates The Ring towards the ortho and para aromatic electrophic substitution.
How can I nitrate an ester with mixed acid?
To get nitration of the ester as the major product in the reaction you will have to use different nitrating agent such as Nitronium tetrafluoroborate (NO2BF4) instead of using mixed acid. Hope this helps… Deepta Chattapadhyay has provided a good answer to this question.