Table of Contents
- 1 When the angle between the two plane mirror is 40 degree how many images will be formed by the mirror?
- 2 How many images will be formed if two plane mirrors are kept at an angle of 60 degree to each other?
- 3 How do you find the angle between two mirrors?
- 4 What is the formula for the number of images formed?
When the angle between the two plane mirror is 40 degree how many images will be formed by the mirror?
Thus, the images formed will be 5. So, $\dfrac{{360^\circ }}{{40^\circ }}$$ = $ 9, where 9 is an odd number. Thus, the images formed will be 9.
How many images will be formed if two plane mirrors are kept at an angle of 60 degree to each other?
60 degeree=360/60 = 6-1=5 images.
What type of image is formed by plane mirror?
virtual
Images formed by plane mirrors are virtual, upright, left-right reversed, the same distance from the mirror as the object’s distance, and the same size as the object.
How many images will be formed if two plane mirrors are placed?
The formula to find no of images (n) = (360 /X) where X is angle between mirror. Here X=45. Hence total 8 image will be formed. How many images will be formed if two plane mirrors placed at angle 90 degree?
How do you find the angle between two mirrors?
This is because the image formed in the first mirror acts as the object for the second mirror. In this case, if you place the mirrors at right angle (90°), then the formula 360/n -1 is used, where n is the angle between the mirror. Here]
What is the formula for the number of images formed?
The formula for number of images formed by two plane mirrors placed at certain angle is (360/n). [where n=angle between the mirrors] The most important thing to remember is that, every time the number of images formed are only ODD numbers. ( for the reason of odd number formation, refer textbooks like hc verma)
How many images are there if 360/45 is even?
If 360/A is even then number of images is n= (360/A)-1. In our problem 360/45=8 (even), therefore number of images=7. More information: if 360/A is odd and object is placed symmetrically on the angle bisector then ,n= (360/A)-1. If object is not placed on the angle bisector then n=360/A if 360/A is odd as mentioned above.