Table of Contents
- 1 What volume of oxygen shall be produced by heating 49 gram of KClO3?
- 2 How many grams of oxygen evolved when 122.5 g Potassium chlorate is heated?
- 3 What is the volume of o2 obtained at STP?
- 4 What is the molar volume of a gas at standard temperature and pressure Brainly?
- 5 How many moles of oxygen are produced when potassium chlorate decomposes?
What volume of oxygen shall be produced by heating 49 gram of KClO3?
×12.25 =3.36 L.
What volume of oxygen will be produced by heating 245kg of pure KClO3 at STP?
or 245 g of KClO2 produce O2 = 3 x 22.4 lits.
What volume of oxygen is obtained when 10.0 g of potassium chlorate is decomposed at STP?
Approx. 3L of dioxygen gas will be evolved.
How many grams of oxygen evolved when 122.5 g Potassium chlorate is heated?
∴ 2 × 122.5 g of KClO₃ forms 32 g of Oxygen.
What is the formula for potassium chlorate?
KClO3
Potassium chlorate/Formula
What volume of oxygen at STP will be obtained by the action of heat on 20g of kclo3?
molar volume of o2 at stp =22.4L….from(2×123.5) gms of kclo3, volume of o2 obtained=(3×22.4) L,from 20gm of kclo3, volume of o2 obtained=3×22.4×20÷(2×123.5) litres………
What is the volume of o2 obtained at STP?
= 3.36 L of O2 of STP.
How many moles are in potassium chlorate?
The answer is 122.5495. We assume you are converting between grams Potassium Chlorate and mole. You can view more details on each measurement unit: molecular weight of Potassium Chlorate or mol The molecular formula for Potassium Chlorate is KClO3. The SI base unit for amount of substance is the mole.
How many moles of oxygen are obtained by heating it mole of potassium chlorate?
12 moles of oxygen will obtain by heating 8 mol of potassium chlorate.
What is the molar volume of a gas at standard temperature and pressure Brainly?
At STP, an ideal gas has a volume of about 22.4 L—this is referred to as the standard molar volume (Figure 10).
What volume of oxygen gas is released at STP?
The volume that is occupied by 1 mol of an ideal gas at STP, which is 22.4 L. What volume would 3.01•1023 molecules of oxygen gas occupy at STP?
What is the balanced equation for the decomposition of potassium chlorate?
Potassium chlorate, KClO3, will decompose upon heating to form potassium chloride, KCl, and oxygen gas, O2, according to the following balanced chemical equation 2KClO3 (s] Δaa − → 2KCl(s] +3O2 (g] ↑ The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose.
How many moles of oxygen are produced when potassium chlorate decomposes?
The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose. This will be the theoretical yield of the reaction, i.e. what you get when the reaction has a 100\% yield.
What is the reaction between potassium chlorate and KClO3?
Potassium chlorate, KClO3, will decompose upon heating to form potassium chloride, KCl, and oxygen gas, O2, according to the following balanced chemical equation The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose.
How to find the gram molecular mass of potassium chloride?
Find the gram molecular mass of Potassium Chloride. = 74.4 grams / mole. The reaction will produce 15.3 g of KCl. 1. Write the balanced equation.