Table of Contents
- 1 What number must be added to 1080 to make it a perfect square?
- 2 How many factors does 1080 have?
- 3 What smallest number Can 1080 be divided by to make the divided a perfect cube?
- 4 IS 128 a perfect square?
- 5 How to recur for every number whose square is smaller than n?
- 6 Is Min square sum problem a dynamic programming problem?
What number must be added to 1080 to make it a perfect square?
3
Hence answer is 3, i.e. 3 factors of 1080 are perfect squares. Note: Factor is a number or algebraic expression that divides another number or expression evenly, i.e. with no remainder.
How many factors does 1080 have?
32 factors
There are 32 factors of 1080, of which the following are its prime factors 2, 3, 5. The Prime Factorization of 1080 is 23 × 33 × 51.
How many factors of 256 which are perfect square?
5 factors
∴ There are 5 factors of 256 which are the perfect square.
What are the divisors of 1080?
The divisors of 1080 are 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 27, 30, 36, 40, 45, 54, 60, 72, 90, 108, 120, 135, 180, 216, 270, 360, 540, and 1080 itself.
What smallest number Can 1080 be divided by to make the divided a perfect cube?
1080=2×2×2×3×3×3×5. We know that a number is a perfect cube root only if it has factors in a pair of 3. Here in 1080, there is a pair of 2 and 3, but 5 is the only remaint number, so we’ve to divide the number 1080 by 5 to get it as perfect cube root.
IS 128 a perfect square?
The square root of 128 is a number which when multiplied by itself, results in the number 128. The value of a square root can be a decimal or a whole number, or an integer….Square of 128: 128² = 16,384.
1. | What Is the Square Root of 128? |
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6. | Important Notes on Square Root of 128 |
What is a perfect square in math?
A perfect square is an integer that is the square of an integer; in other words, it is the product of some integer with itself. For example, 1, 4, 9, and 16 are perfect squares while 3 and 11 are not.
How do you find the minimum number of squares for 100?
Note that 1 is a square and we can always break a number as (1*1 + 1*1 + 1*1 + …). Given a number n, find the minimum number of squares that sum to X. 100 can be written as 10 2.
How to recur for every number whose square is smaller than n?
Recommended: Please solve it on “ PRACTICE ” first, before moving on to the solution. The idea is simple, we start from 1 and go to a number whose square is smaller than or equals n. For every number x, we recur for n-x. Below is the recursive formula. Below is a simple recursive solution based on the above recursive formula. // n (1*1 + 1*1 + ..)
Is Min square sum problem a dynamic programming problem?
So min square sum problem has both properties (see this and this) of a dynamic programming problem. Like other typical Dynamic Programming (DP) problems, recomputations of the same subproblems can be avoided by constructing a temporary array table [] [] in a bottom-up manner.