What is the ratio of the area of the square compared to a triangle?
The ratio of the area of two similar triangles is equal to the square of the ratio of any pair of the corresponding sides of the similar triangles. For example, for any two similar triangles ΔABC and ΔDEF, Area of ΔABC/Area of ΔDEF = (AB)2/(DE)2 = (BC)2/(EF)2 = (AC)2(DF)2.
What is the ratio of the area of an equilateral triangle to the area of its Circumcircle?
We know that area of circle = π*r2, where r is the radius of given circle. We also know that radius of Circumcircle of an equilateral triangle = (side of the equilateral triangle)/ √3. Therefore, area = π*r2 = π*a2/3.
What is the ratio of areas of a square and an Equilaterial Traingle having equal sides?
The side of a square is equal to the side of an equilateral triangle ,The ratio of their areas is. Let the side of the square = side of the triangle = a. then , area of the squarearea of the triangle =a2√34=4√3=4:√3.
What is the ratio of areas of Incircle and circumcircle of an equilateral triangle 1 2?
1 : 2
The ratio of the areas of the incircle and the circumcircle of an equilateral triangle is: 1 : 2.
What is the ratio of the area of triangle to square?
The ratio of the area of the triangle to the area of the square is A circle is inscribed in an equilateral triangle and a square is inscribed in the circle. The ratio of the area of the triangle to the area of the square is Clearly, centre of triangle , circle and square coincides.
What happens when a circle is inscribed in an equilateral triangle?
A circle is inscribed in an equilateral triangle and a square is inscribed in the circle. The ratio of the area of the triangle to the area of the square is Clearly, centre of triangle , circle and square coincides.
How do you find the area of an equilateral triangle?
You can draw an equilateral triangle inside the circle, with vertices where the circle touches the outer triangle. Now, you know how to calculate the area of that inner triangle from Sal’s video. Specifically, this is 3/4 * r^2 * sqrt (3).
How do you solve a 30 60 90 right triangle?
I don’t think you even need trig to solve the problem. and from there, use the rules of the side of a 30:60:90 right triangle. You can find the side a/2 and the line from the center of the circle to where it reaches side a perpendicularly. With these you can find the eight of the triangle and the base.