Table of Contents
What is the range of a projectile if the initial velocity?
The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin 2 θ i g . The maximum height of an object, given the initial launch angle and initial velocity is found with:h=v2isin2θi2g h = v i 2 sin 2 θ i 2 g .
What is the maximum velocity of a projectile?
So at maximum height, the velocity of a projectile is vcosQ and as the vertical velocity is 0, the horizontal velocity is the only velocity and no resultant needs to be calculated.
How the initial speed affecting the range and the maximum height of the projectile?
Just like the case of the time of flight, we see that maximum height reached by the projectile depends on both initial speed and the angle of projection (θ). Greater the initial velocity and greater the angle of projection from horizontal direction, greater is the height attained by the projectile.
How do you calculate the range of a projectile?
To determine the range R of the projectile,we multiply the horizontal component of the velocity of projection with total time taken by the body after leaving the point of projection.Thus: Thus the range of the projectile depends upon the velocity of projection and the angle of projection.
What is the formula for projectile?
The maximum height of a projectile is calculated with the equation h = vy^2/2g, where g is the gravitational acceleration on Earth, 9.81 meters per second, h is the maximum height and vy is the vertical component of the projectile’s velocity. If the angle of launch or the velocity of the projectile are not known, these quantities can be derived.
What is the horizontal range of a projectile?
The horizontal range of a projectile is the distance along the horizontal plane it would travel, before reaching the same vertical position as it started from. The horizontal range depends on the initial velocity v0, the launch angle θ, and the acceleration due to gravity. The unit of horizontal range is meters (m).
What is the equation for projectile motion?
Let’s sum that up to form the most important projectile motion equations: Horizontal velocity component: vx = v * cos(θ) Vertical velocity component: vy = v * sin(θ) Time of flight: t = 2 * vy / g Range of the projectile: R = 2* vx * vy / g Maximum height: ymax = vy^2 / (2 * g)