Table of Contents
- 1 What is the probability that in a class of 25 students no two students will have the same birth date?
- 2 What is the probability that at least two students of a class of size 23 have the same birthday?
- 3 What is the probability of each student being born on 365 days?
- 4 How many possible combinations of birthdays are there in a group?
What is the probability that in a class of 25 students no two students will have the same birth date?
The probability is (approximately) 43.13\%.
What is the probability that at least 2 of the people in the class share the same birthday?
In a room of just 23 people there’s a 50-50 chance of at least two people having the same birthday. In a room of 75 there’s a 99.9\% chance of at least two people matching.
What is the probability that at least two students of a class of size 23 have the same birthday?
a 50 percent
You can test it and see mathematical probability in action! The birthday paradox, also known as the birthday problem, states that in a random group of 23 people, there is about a 50 percent chance that two people have the same birthday.
What is the probability that among 25 people at least 2 have their birthday on the same day of the year?
Answer: The Probability that of 25 Randomly Selected Students, at Least Two, Share the same Birthday is 0.5687.
What is the probability of each student being born on 365 days?
Let’s take this step by step: The first student can be born on any day, so we’ll give him a probability of 365/365. The next student is now limited to 364 possible days, so the second student’s probability is 364/365. The third student may be born on any of the remaining 363 days, so 363/365.
What is the probability of each person having her birthday?
So, firstly we will have to select that day and it can be done in 365 C 1 ways. Now, the probability of each person having her birthday on the selected day is 1 365. One approach to answer this problem is to first compute the probability they don’t have the same birthday.
How many possible combinations of birthdays are there in a group?
If one assumes for simplicity that a year contains 365 days and that each day is equally likely to be the birthday of a randomly selected person, then in a group of n people there are 365 n possible combinations of birthdays. The simplest solution is to determine the probability of no matching birthdays and then subtract this probability from 1.
How many ways can two people have the same birthday?
The number of ways that all n people can have different birthdays is then 365 × 364 ×⋯× (365 − n + 1), so that the probability that at least two have the same birthday is.