Table of Contents
- 1 What is the largest integer n such that 33 is divisible by 2 N?
- 2 What would be the value of N for which N 2 )- 1 is divisible by 8?
- 3 How to prove 33 is divisible by 2 15?
- 4 What is maximum value of n for which 352 is divisible by 352n?
- 5 What is the maximum value of N?
- 6 What is the divisibility of 33?
- 7 What is the largest power of 2 and 3?
- 8 How many multiples of 2 are less than 33?
- 9 How do you find the minimum value of a power prime?
What is the largest integer n such that 33 is divisible by 2 N?
Thus, 31 is the largest integer such that 33! Is divisible by 2n.
What would be the value of N for which N 2 )- 1 is divisible by 8?
Any odd positive integer is in the form of 4p + 1 or 4p+ 3 for some integer p. ⇒ (n2 – 1) is divisible by 8. ⇒ n2– 1 is divisible by 8. Therefore, n2– 1 is divisible by 8 if n is an odd positive integer.
How to prove 33 is divisible by 2 15?
For prime number p and n∈N, the highest power of p that divides n! is given by, ∑k≥1[npk]. So, 33! can be divided by 231. So, 33! is divisible by 215 and maximun value of n is 31 such that 33! is divisible by 231.
Is 33 divisible by 3 yes or no?
Since the answer to our division is a whole number, we know that 33 is divisible by 3.
Is 34 divisible by?
When we list them out like this it’s easy to see that the numbers which 34 is divisible by are 1, 2, 17, and 34.
What is maximum value of n for which 352 is divisible by 352n?
Hence 34 is the answer.
What is the maximum value of N?
∴ The largest value of n will be 48.
What is the divisibility of 33?
Division rule of 33 : If number is divisible by 3 and 11, then number is also divisible by 33. Sum of digits of 5283 is 5+2+8+3=18, which is divisible by 3.
What are the multiples of 33?
The first 5 multiples of 33 are 66, 99, 132, 165. The sum of the first 5 multiples of 33 is 462 and the average of the first 5 multiples of 33 is 92.4. Multiples of 33: 66, 99, 132, 165, 198, 231, 264, 297, 330, 363, 396 and so on.
How to find the highest power of P that divides m factorial?
Given an integer M and a prime number p, find the largest x (power) such that pˣ (x raised to power p) divides M! (factorial). Here , the given Number M is divided by p¹,p²,p³ …. until we get 1 after division. Then all the consecutive quotient are added including 1 which gives the highest power of p which divides M factorial .
What is the largest power of 2 and 3?
Explanation: 2⁹⁷ divides 100! and 97 is the largest such power of 2. Explanation: 3⁴⁸ divides 100! and 48 is the largest such power of 3. The most basic approach to this problem is by going step by step into the subparts lying below.
How many multiples of 2 are less than 33?
First we find the multiples of 2 which are less than 33! . 16 multiples of 2 are less than 33! . So in 33!, all these 16 numbers will contribute one power of 2. Similarly, all multiples of 4 will contribute one extra power each. Similarly for multiples of 23, 24, 25. Number of Multiples of 22 less than 33! are 8.
How do you find the minimum value of a power prime?
If on dividing N by i (N=N/i) if we get a N which is greater than 2 then we again pass into the function find power prime to get the highest power of N that divides fact (fact!) . We simulatneously keep on finding the minimum value of the res that is returned by find power prime and thus in the end we get the Minimum result .