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What is probability that a leap year selected at random would contain 53 Saturdays?
A leap year has 366 days or 52 weeks and 2 odd days. The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays is 2/7.
What is the probability that a leap year has 53 Saturdays and 53?
in that, we have 52 weeks and 2 days. we have 2 days extra. these extra two days can be any days of the week like Sunday-Monday and so on. the probability of 53 Saturdays or Sundays = 2/7.
What is the probability that leap year selected at random will contain 53 Sundays or 53 Fridays?
= 3/7.
What is the probability that a leap year selected at random?
Hence, a leap year has 52 Sundays. Hence, we have 7 possibilities. From the possibilities, we have two Sundays in it. Hence, the required probability is 2/7.
What is the probability that a leap year selected at random has 53 Mondays?
In a leap year there will be 52 Mondays and 2 days will be left. Of these total 7 outcomes, the favourable outcomes are 2. Hence the probability of getting 53 Mondays in a leap year = 2/7.
What is the probability that the leap year selected at random?
What is the probability that a leap year has 53 Mondays?
In a leap year there will be 52 Mondays and 2 days will be left. Of these total 7 outcomes, the favourable outcomes are 2. Hence, the probability of getting 53 Mondays in a leap year P(E) = 2/7.
What is the probability that a randomly taken leap year has 52 Sundays?
5/7
In a leap year, we have 366 days. So, we have 52 weeks and 2 days. Out of these, 7 pairs of combinations, only 2 pairs have Sunday, and the other 5 pairs do not have Sundays. Therefore, the probability that a leap year will have only 52 Sundays is 5/7.
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