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How many weighings of a balance scale are needed to find a counterfeit coin among 12 coins?
Hence the minimum number of weighings required to find the fake coin using a two pan balance is 3. Start by numbering the coins 1.. 12. put 1,2,3,4 on the left scale, 5,6,7,8 on the right.
How many weighing Do you need to find the counterfeit coin among 81 coins?
So, with 4 weighings, you can do upto 81 coins this method. You weigh the two 27 coin ones. If they are not equal, you pick the one that weighs the least, if they are equal, then you grab the group of 26 that you didn’t weigh. Set aside the other two groups as the counterfeit coin are not there.
Where is the light counterfeit coin among eight coins in two weighings?
Weighing Coins, Balls, What Not …
- The Oddball Problem, B. Bundy.
- Weighing 12 coins, Dyson and Lyness’ solution.
- Weighing 12 coins, W. McWorter.
- Thought Less Mathematics, D. Newman.
- Weighing with counterbalances.
- Odd Coin Problems, J. Wert. Odd Coin Problems, a shortened exposition.
- Six Balls, Two Weighings.
- 12 Coins in Verse.
Are all coins the same weight?
23 coins are the same weight, but 1 coin is either heavier or lighter. All you are given is a set of BALANCE scales, which can compare the weight of any two sets of coins out of the total set of 24 coins.
How do you identify a fake coin?
You can put this solution on YOUR website! Given 12 coins such that exactly one of them is fake (lighter or heavier than the rest, but it is unknown whether the fake coin is heavier or lighter), and a two pan scale, devise a procedure to identify the fake coin and whether it is heavier or lighter by doing no more than 3 weighings.
How many of the 12 coins are false?
There are 12 coins. One of them is false; it weights differently. It is not known, if the false coin is heavier or lighter than the right coins. How to find the false coin by three weighs on a simple scale? – Quora There are 12 coins. One of them is false; it weights differently.
How many coins are needed to determine whether a coin is genuine?
We are given 5 coins, a group of 4 coins out of which one coin is defective (we don’t know whether it is heavier or lighter), and one coin is genuine. How many weighing are required in worst case to figure out the odd coin whether it is heavier or lighter?
How many coins are there and how much do they weigh?
(And by the way, his original puzzle allow the possibility that there may be no false coin.) There are 9 coins. 8 coins weigh 1 gram and 1 coin weighs 2 grams. How will you find out the heavier coin in a minimum number of weighings and how many weighings will be needed? Originally Answered: There are 9 coins. 8 are of 1 gm and 1 is of 2 grams.