How many numbers in all from 1 to 100 are the multiples of 6?
Number of multiples of 6 between 1 and 100=100/6=16 Since the range starts from zero, we need to take zero too. [zero is a multiple of every integer (except zero itself)]. So, answer =16+1=17 Number of multiples of 6 between 1 and 34=34/6=5 Since the range is −6 to 34, we need to take −6 and zero.
How do you find the multiples of a number?
To find multiples of a number, multiply the number by any whole number. For example, 5 × 3 = 15 and so, 15 is the third multiple of 5. For example, the first 5 multiples of 4 are 4, 8, 12, 16 and 20. 1 × 4 = 4, therefore the 1st multiple of 4 is 4.
What is the sum of first 7 multiples of 5?
The first seven multiples of 5 is 5,10,15,20,25,30,35. So, we have to add them. 5+10+15+20+25+30+35 = 140. So, 140 is the answer.
What is the sum of all multiples of 3 between 1 and 1000?
Therefore the sum of all multiples of 3 between 1 and 1000 is 166833.
What is the sum of all multiples of 5 from 1-100?
The sum of the numbers fro 1 to 20 is 20 x 21 / 2 = 210. So the sum of all the integers that are multiples of 5 from 1 to 100 is 5 x 210 = 1050. I’m still confused about the difference between data analyst, data engineer, and a data scientist.
How to find the sum of multiples in C++?
So we can get the sum of multiples as: sum = a * (Summation of 1 to m [natural numbers from 1 to m]) sum = 4 * (m* (m+1) / 2) sum = 4 * (5*6 / 2) = 4 * 15 = 60. C++.
How do you find the sum of multiples of a loop?
We can modify the loop as i = a, i <= n, i = i + a to reduce the number of iterations.But it will also take O (m) time if there is m multiples of a. a = 4 and N = 23, number of multiples of a, m = N/a (integer division). The multiples are 4, 8, 12, 16, 20. We can write it as 4 X [1, 2, 3, 4, 5]. So we can get the sum of multiples as:
What is the sum of multiples of a and N?
a = 4 and N = 23, number of multiples of a, m = N/a(integer division). The multiples are 4, 8, 12, 16, 20. We can write it as 4 X [1, 2, 3, 4, 5]. So we can get the sum of multiples as: