Table of Contents
How many numbers can be formed with 7 digits?
How Many 7-Digit Numbers are there in all? 7-digit numbers start from 1000000 and end with 9999999. There are ninety lakh (90,00,000) 7-digit numbers in all.
What surprise do you get when you multiply a three digit number by 7 then by 11 then by 13?
Hi Sherrie. When you multiply 7 x 11 x 13, you get 1 001. That’s 1000 + 1. So when you multiply a three digit number (let’s write it as “abc”) by this, then abc (1000 + 1) = abc x 1000 + abc x 1 = abc 000 + abc = abcabc.
How many 7 digit numbers can be formed using the digits 1/2 0?
=(420-60)=360.
What is a number divisible by 7 11 and 13?
If you multiply 7 x 11 x 13 you get 1001 and if you take 1001 times any three- digit number you get a six-digit number where the original three-digit number repeats. Therefore, your original six-digit number would be divisible by 1001 or 7, 11, and 13.
What should be multiplied to 2880?
Prime factorisation of 2880 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 5. Hence, 5 should be multiply to 2880 to make it perfect square.
How can we make 6 numbers using 3 digits?
We can make 6 numbers using 3 digits and without repetitions of the digits. LOOK AT THE TREE DIAGRAM ABOVE. We have 3 choices for the first digit, 2 choices for the second digit and 1 choice for the third digit. There is a special notation for the product 3 × 2 × 1 = 3! and it is read 3 factorial. We also define 0! = 1.
How to find the product of the digits of a number?
Given a number, the task is to find the product of the digits of a number. Recommended: Please try your approach on {IDE} first, before moving on to the solution. Get the rightmost digit of the number with help of remainder ‘\%’ operator by dividing it with 10 and multiply it with product.
What is the largest 6 digit number and the smallest 4-digit number?
The largest 6-digit number is 9,99,999 and the smallest 4-digit number is 1000. Their difference is: 9,99,999 – 1000 = 9,98,999. The predecessor of the difference is 9,98,998. Ready to see the world through math’s eyes?
How do you arrange 2 digits out of 4 in order?
The above problem is that of arranging 2 digits out of 4 in a specific order. This is also called permutating. The most important idea in permutations is that order is important. When you use the digits 3 and 4 to make a number, the number 34 and 43 are different hence the order of the digits 3 and 4 is important. n P r = n! / (n – r)!