Table of Contents
How many 6 number combinations are there in the numbers 0 to 9?
There are 999999 – 100000 + 1 possible ways to make 6 digit numbers using the dgits 1 – 9. There are 900000 possible ways to get 6 digit numbers using 0 – 9.
How many 6-digit number are there with no digit repeated?
Finally you can form 5*5*4*3*2*1=600 6-digit numbers using the given numbers…. So the answer of your question is 600.. Thanks…!! Originally Answered: How many 6-digit numbers can be formed without repeating any digit from the digits 0,1,2,3,4,5?
Can a 6-digit number start with 0?
Do not allow the number to start with a zero. So I know that there are 10 possible digits that can be selected, each time the pool of selected digits gets smaller. The first digit cannot be zero therefore there are 9 possibilities for this digit.
What is the probability of a 6 digit number with no repeats?
The probability of a 6 digits number with no repeats is basically the number of permutations of 6 digits with no repetitions among the set of all possible numbers, so the probability is given by P (E) = P (10, 6) 10 6 = 0.1512.
What is the probability of a phone number being 9^7?
Counting the number of such phone numbers is easy: there are $9 imes 9 imes \\dots imes 9 = 9^7$ possibilities in this event. As there are $10^7$ possibilities in total, the probability you are looking for is $1-\\left(\\frac{9}{10})ight)^7$.
What is the probability that all two numbers are divisible by 4?
The event that the two digit numbers formed by the digits 1, 2, 3, 4, 5 are divisible by 4 = {12, 24, 32, 44, 52} Hence, the required probability = 5/25 = 1/5. Was this answer helpful? Thank you.
What is the probability that my Number is 4109?
Your colleague is right. If your digits are randomly and independently selected (assuming equal likelihood for each digit), the chance that your number is 4109 is nothing more complicated than: all multiplied together. That’s ( 1 / 10) 4, as your colleague says. Where would permutations come into it?