Table of Contents

- 1 For what value of k for which the equation x2 4x K 0 has distinct real roots?
- 2 For what values of k the roots of the equation x2 4x k 0 are real A 2 B 4 C 4 D 1 4?
- 3 For what values of k the equation x2 2 K − 4 x 2k 0 has equal roots?
- 4 For what value of K has equal roots?
- 5 For what value of k is the equation x 2?
- 6 Which equation has imaginary and unequal roots?

## For what value of k for which the equation x2 4x K 0 has distinct real roots?

The given quadric equation is x2 + 4x + k = 0, and roots are real and distinct. Then find the value of k. Therefore, the value of k < 4 .

### For what values of k the roots of the equation x2 4x k 0 are real A 2 B 4 C 4 D 1 4?

Answer: The value of k must be less than or equal to 4.

#### For what values of k the equation x2 2 K − 4 x 2k 0 has equal roots?

Correct Option: B Since, the root are equal, we have D = 0. Hence, the value of k 8 or 2.

**How do you show that an equation has real and distinct roots?**

The value of the discriminant shows how many roots f(x) has: – If b2 – 4ac > 0 then the quadratic function has two distinct real roots. – If b2 – 4ac = 0 then the quadratic function has one repeated real root. – If b2 – 4ac < 0 then the quadratic function has no real roots.

**For what value of k for which the quadratic equation 16x² 4kx 9 0 has real and equal roots?**

Answer: The value of k is 6,-6.

## For what value of K has equal roots?

Now, as mentioned above, for the equation to have equal roots, D=0. Thus, for the given equation to have equal roots, the value of k should be $ \pm 2\sqrt{6} $ .

### For what value of k is the equation x 2?

Therefore, the value of k =± 4 .

#### Which equation has imaginary and unequal roots?

When a, b, and c are real numbers, a ≠ 0 and the discriminant is positive, then the roots α and β of the quadratic equation ax2 +bx+ c = 0 are real and unequal….Nature Of Roots.

b2 – 4ac > 0 | Real and unequal |
---|---|

b2 – 4ac = 0 | Real and equal |

b2 – 4ac < 0 | Unequal and Imaginary |

b2 – 4ac > 0 (is a perfect square) | Real, rational and unequal |

**Which of the following equations has 2 as a root * 1 point a X² 4x 5 0 B X² 3x 12 0 C 2x² 7x 6 0 D 3x² 6x 2 0?**

⇝0. We can see that option (C) is having the correct root as the Answer is 0 , which means it’s root is 2 , So we got our answer i.e., 2x² – 7x + 6 = 0 .