Table of Contents
Which list shows numbers that are all multiples of 3?
The first ten multiples of 3 are listed below: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30.
What are all the multiples of 3 and 5?
common multiples of 3 and 5 are 15,30,45,60,90.
How do you write multiples of 3 in python?
For all number from 1 to n,
- if number is divisible by 3 and 5 both, put “FizzBuzz”
- otherwise when number is divisible by 3, put “Fizz”
- otherwise when number is divisible by 5, put “Buzz”
- otherwise write the number as string.
How do you find the sum of all the multiples of 3 or 5 below 1000?
here a is 3 or 5 or 15, and n is 999 or 1000 but 999 is best, and then sum multiples of 3: 3((333)∗(333+1)/2)=166833 plus multiples of 5: 5((199)∗(199+1)/2)=99500; and subtract multiples of 15 15((66)+(66+1)/2)=33165 to get 233168.
What is the least common multiple of 5 and 10?
10
Answer: LCM of 5 and 10 is 10.
How do you find multiples of a number?
Multiples of a number are the result of multiplying a number by a whole number. For example, multiply 2.5 (not a whole number) by 5 (a whole number). The result is 12.5, which means that 12.5 is a multiple of 2.5 since it was multiplied by 5 (a whole number). Compare this to multiplying 2.5 by 5.5.
What is the sum of all 3 digit multiples of 3 or 5?
These are the numbers 0,1,2,3,…,333, all of them multiplied by 3. The first sum is or 166833. You have numbers 0,5,10,15,…,995. These are the numbers 0,1,2,3,…,199, all of them multiplied by 5.
How to find the sum of every third and fifth natural number?
By applying the above formula to n =999 and d =3 and d =5 we get the sums for every third and fifth natural number. Adding those together is almost our answer but we must first subtract the sum of every 15 th natural number (3 × 5) as it is counted twice: once in the 3 summation and once again in the 5 summation.
What is the sum of all natural numbers less than 100?
S (3and5) is the sum of all natural numbers less than 100, which are multiples of both 3 and 5. Since gcd (3,5) = 1 , a number is a multiple of 3 and 5 iff it is a multiple of 15.
What is the sum of every 15th natural number?
Adding those together is almost our answer but we must first subtract the sum of every 15 th natural number (3 × 5) as it is counted twice: once in the 3 summation and once again in the 5 summation. This is a typical application of the inclusion–exclusion principle.