Table of Contents
- 1 What is the smallest number that is exactly divisible by 32?
- 2 What is the smallest number that is exactly divisible by 32 and 24?
- 3 What is the smallest number which is divisible by 16 24 26 and 32 when it is increased by 5?
- 4 What is the smallest number which on being added to 21 to it is exactly divisible by 36 60 and 42?
- 5 Which number is exactly divisible by 32 36 48 96 and 96?
- 6 What is the smallest number that is exactly divisible by 23?
- 7 How to find the LCM of the numbers 1 to N?
What is the smallest number that is exactly divisible by 32?
Hence, the smallest number will be 288.
What is the smallest number that is exactly divisible by 32 and 24?
Step-by-step explanation: The smallest number which is divisible by 32, 16 ,and 24 is 96.
What is the smallest 4 digit number divisible by 18 24 and 32?
1152
Hence 1152 is the smallest four digit number divisible by 18, 24 and 32.
What is the smallest number which is divisible by 16 24 26 and 32 when it is increased by 5?
Answer: L.c.m=24,26,16,32=1068. and incremented=5and ans = 1068+5=1073.
What is the smallest number which on being added to 21 to it is exactly divisible by 36 60 and 42?
R D Sharma – Mathematics 9 First We have to find the L.C.M of 32, 36, 48, 96 & then Subtract 23 from the L C.M & then the remaining number will be your required number. The required smallest number is 265.
What is the smallest number divisible by 18 24 and 54?
Answer: 2 is divisible by 18,24,54.
Which number is exactly divisible by 32 36 48 96 and 96?
After subtracting 23, the remaining number will be the required number. 265 is the required smallest number which, on being added 23 to it, is exactly divisible by 32, 36, 48 and 96. Answer. First We have to find the L.C.M of 32, 36, 48, 96 & then Subtract 23 from the L C.M & then the remaining number will be your required number.
What is the smallest number that is exactly divisible by 23?
After subtracting 23, the remaining number will be the required number. 265 is the required smallest number which, on being added 23 to it, is exactly divisible by 32, 36, 48 and 96. Answer.
What is the smallest number that can be added 23 times?
Hence, the required smallest number is 553 when added 23 to it exactly divisible by 32,36,48 and 96.
How to find the LCM of the numbers 1 to N?
If you observe carefully the ans must be the LCM of the numbers 1 to n . Initialize ans = 1. Iterate over all the numbers from i = 1 to i = n. At the i’th iteration ans = LCM (1, 2, …….., i). This can be done easily as LCM (1, 2, …., i) = LCM (ans, i) . Note : In C++ code, the answer quickly exceeds the integer limit, even the long long limit.