Table of Contents
- 1 How much memory can 20-bit data bus address?
- 2 How much memory can access if address bus is 16 bit?
- 3 What is size of address bus in 8085?
- 4 How many storage locations are available when a memory device has 11 address lines?
- 5 What is the address bus size of the memory?
- 6 How many megabits are in a 20 bit address?
How much memory can 20-bit data bus address?
For example, an 8-bit-byte-addressable machine with a 20-bit address bus (e.g. Intel 8086) can address 220 (1,048,576) memory locations, or one MiB of memory, while a 32-bit bus (e.g. Intel 80386) addresses 232 (4,294,967,296) locations, or a 4 GiB address space.
How many memory locations can the 8085 Access if it has a 20-bit address bus?
Address Bus − 8085 has 16-bit address bus while 8086 has 20-bit address bus. Memory − 8085 can access up to 64Kb, whereas 8086 can access up to 1 Mb of memory.
Can be located by a 20-bit address bus?
Q. | A 20-bit address bus can locate ________. |
---|---|
B. | 2,097,152 locations |
C. | 4,194,304 locations |
D. | 8,388,608 locations |
Answer» a. 1,048,576 locations |
How much memory can access if address bus is 16 bit?
A 16-bit integer can store 216 (or 65,536) distinct values. In an unsigned representation, these values are the integers between 0 and 65,535; using two’s complement, possible values range from −32,768 to 32,767. Hence, a processor with 16-bit memory addresses can directly access 64 KB of byte-addressable memory.
What is size of address bus?
Address Bus Size The size of the address bus determines how much memory the CPU can address directly. For example, a 20-bit address bus can access up to one megabyte (1MB); 24 bits reaches 16MB, and 32 bits can handle four gigabytes (GB).
How big is the address space for a microcontroller whose address bus is 20 bits wide?
1 MB
Buses and operation A 20-bit external address bus provides a 1 MB physical address space (220 = 1,048,576). This address space is addressed by means of internal memory “segmentation”.
What is size of address bus in 8085?
16 Bit
Length of Address Bus of 8085 microprocessor is 16 Bit (That is, Four Hexadecimal Digits), ranging from 0000 H to FFFF H, (H denotes Hexadecimal). The microprocessor 8085 can transfer maximum 16 bit address which means it can address 65, 536 different memory location.
What is address bus data bus and control bus?
Address bus – carries memory addresses from the processor to other components such as primary storage and input/output devices. Data bus – carries the data between the processor and other components. The data bus is bidirectional . Control bus – carries control signals from the processor to other components.
What is the size bits of the address bus in 8086 microprocessor?
8086 has a 20 bit address bus can access upto 220 memory locations ( 1 MB) . It can support upto 64K I/O ports. It provides 14, 16-bit registers.
How many storage locations are available when a memory device has 11 address lines?
Hence there will be 212 storage locations.
How many addresses can a 12 bit address bus?
Hence, a microprocessor with 12-bit memory addresses can directly access 4096 words (4 Kw) of word-addressable memory.
How many bits are used in address bus?
In modern computers, the address buses are generally of 36 bits. With 36 bits of address bus, theoretically, a main memory of 64 GB can be accessed.
What is the address bus size of the memory?
So, address bus size well only tell you number of addressable memory locations and not really the size of the memory. Usually, number of addressable memory locations = number of bytes. So, if you had a 2 bit address bus, you can address 4 locations. Each location could be a 64-bit wide register thus you have 64×4=256 bit (32 byte) of memory.
How many bits are in a 16 bit address bus?
Answer Wiki. The width of the address bus determines the amount of memory a system can address. For example, a system with a 16-bit address bus can address 2^16 memory locations. If each memory location holds one byte (8 bits), the addressable memory space is 644 KB of memory.
How do you calculate the address of a memory cell?
Step 1: calculate the length of the address in bits (n bits) Step 2: calculate the number of memory locations 2^n (bits) Step 3: take the number of memory locations and multiply it by the Byte size of the memory cells. If each cell was 2 bytes for example, would I multiply 2^n bits (for address length) by the 2 Bytes per memory cell.
How many megabits are in a 20 bit address?
In the 8086, each address contains 8bit of data. Then, 2 20 addresses means 2 20 records of size 8bit each. As you known, 2 20 = 1 Mega and 8bit=1Byte so 20bits of address means 1Mega addresses x 8bit = 1MegaByte memory.