Table of Contents
How many numbers between 100 and 300 are divisible by both 3 and 5?
Now between 101 to 300, there are 198 numbers (excluding 101 & 300). For a number to be divisible by 3 & 5, it must be divisible by 15.
What is the last number between 100 to 300 divisible by 13?
16
The possible values for k is 8 to 23. There are in total 16 such values which means there are 16 such numbers in between 100 and 300 which are divisible by 13.
How do you get the sum of all numbers from 1 to 100?
How to Find the Sum of Natural Numbers 1 to 100? The sum of all natural numbers from 1 to 100 is 5050. The total number of natural numbers in this range is 100. So, by applying this value in the formula: S = n/2[2a + (n − 1) × d], we get S=5050.
How many numbers between 1 and 300 are divisible by either 11 or 13 but not by both?
So there are (27-2) + (23-2) = 46 numbers between 1 and 300 divisible by only 11 and only 13 but not both.
How many numbers from 300 are divisible by 3 or 5?
This makes a list of all numbers divisible by either and then prints the length of that list: 140. There are 140 numbers which are divisible by 3 or 5 or both.. In the number from 1–30 ,15 is a number that is divisible by both 3 and 5 so for 300 there will be 10 number that will be divisible by both numb so cancel 10 from the sum result
How many multiples of 5 are there between 1 and 300?
First, find the number of multiples of 3 between 1 and 300 (I assume inclusive). 300 / 3 = 100 multiples of 3. Next, find the number of multiples of 5 between 1 and 300. 300 / 5 = 60 multiples of 5.
Which numbers between 101 & 300 are divisible by LCM(3 5 = 15)?
A word ‘between’ suggests that 300 should not be included in the list. Numbers divisible by both 3 & 5 are the numbers which are divisible by lcm (3, 5) = 15. We’ve to find such numbers between 101 & 300.The first multiple of 15 in this range is 105 & the last one is 285.
How many numbers between 3 and 5 are divisible by 139?
So, the total numbers which divisible by 3 or 5 and between 1~300 is 139. Now done with the long version, here comes the shorter version. But wait, there’s some common multiple between 3 and 5. For every 3 multiple of 5, there’s 1 which is also multiple of 3. This need to be deducted because repetition. Ok, now comes the calculation.
https://www.youtube.com/watch?v=CMu1U9KVNps