Table of Contents
- 1 How many guesses would you need to find a number between 1 and 1000 if you performed a linear search?
- 2 What is the maximum number of comparisons that would be required for a simple binary search?
- 3 How many numbers of comparisons are required in insertion sort to sort a file if the file is already sorted?
- 4 What is the maximum number of comparisons needed by the binary search algorithm when an array contains 1024 elements?
- 5 How to determine number between 1 and 100 in 7 guess?
- 6 How many guesses do you need for a number 1-1024?
How many guesses would you need to find a number between 1 and 1000 if you performed a linear search?
And so on. which responded with 8987, so the average for the 1 to 1000 case, assuming that we always make the guess of the rounded average of the limits of the interval we know that x belongs to, must be 8.987 guesses.
What is the maximum number of comparisons that would be required for a simple binary search?
A binary search of 10,000 items requires at most 14 comparisons. Thus, in terms of the number of comparisons, binary search is much more efficient than sequential search. However, in order to use the binary search approach, the items must be presorted.
What is the maximum guess you need to find a number in 1 1000?
Counting the number of guesses above would give you 10, which is our answer to the maximum number of guesses to find a number between 1 and 1000.
How many numbers of comparisons are required in insertion sort to sort a file if the file is already sorted?
Part (b) of Figure 5.15 shows that only four comparisons are required by the algorithm when the input list is already presorted. This is different from the selection sort algorithm which always requires a fixed number of comparisons to sort N items, regardless of their original order.
What is the maximum number of comparisons needed by the binary search algorithm when an array contains 1024 elements?
11 comparisons
Answer and Explanation: For a sorted list of 1024 elements, a binary search takes at most 11 comparisons.
Is binary search the best way to solve for 1-127?
Binary search is considered the best for this problem – unless you are allowed to ask other questions. Yes. Each guess eliminates one number as well as dividing the remaining numbers into 2. One guess can pick a number from 3 (is your number 2?). 2 guesses can do 7. N guesses can pick a number from 2 N + 1 − 1, so 6 guesses can do it for 1-127.
How to determine number between 1 and 100 in 7 guess?
Why is it that a number selected at random between 1 and 100 can be determined in 7 or less guesses by always guessing the number in the middle of the remaining values, given that you’re told whether your previous guess was too high or low? Here’s a link to the earlier thread: Guessing number between 1-100 always can always be guessed in 7 guess.
How many guesses do you need for a number 1-1024?
For any number 1–1024, you need only 10 guesses — 512, 256, 128, 64, 32, 16, 8, 4, 2, 1 — start with 512, if less then 256, if more then 512+256, and so on until you either hit the number or have incremented by 2 and the answer is higher or lower.
How many questions are sufficient for the numbers from 1 to 100?
For k = 6 we get N ( 6) = 127 so we can differentiate between 127 numbers. Therefore 6 questions are sufficient for the numbers from 1 to 100. The first question always asks for the number 64.