How many grams of H2SO4 are needed to neutralize?
One mole of H2SO4 (98 grams) will neutralize two moles on NaOH (40 grams per mole).
How many moles of NaOH are required to neutralize?
A 1:1 mole ratio basically means that the reaction consumes equal numbers of moles of sodium hydroxide and of hydrochloric acid. In other words, for every 1 mole of sodium hydroxide that takes part in the reaction, you need 1 mole of hydrochloric acid to neutralize it.
How many milliliters of NaOH are needed to completely neutralize acid?
Let the volume of the NaOH solution required be V1 . When the acid and base are allowed to react, a neutralization reaction occurs. Thus, we require 10.0 mL of NaOH solution to completely neutralize the HCl solution.
What mole ratio of NaOH to H2SO4 is needed in a neutralization reaction?
Based on the equation, the mole ratio between NaOH and H2SO4 is 2:1, meaning that it takes twice the amount of NaOH as H2SO4, for the base to completely neutralize the acid and produce sodium sulfate and water.
How many mL of a .10 m NaOH solution are needed to neutralize 15 mL of a .20 m h3po4 solution?
30 mL is your answer.
How much H2SO4 will it take to neutralize NaOH?
One mole of H2SO4 (98 grams) will neutralize two moles on NaOH (40 grams per mole). You probably won’t have concentrated sulfuric acid, so amount needed would have to adjusted by the dilution factor. The Rock reveals the key to success for normal people.
What is the molecular weight of H2SO4 in 8g of NaOH?
1 Mole of NaOH is (23+16+1) = 40 g so 8g = 1/5 mole and we therefore need 1/10 mole of H2SO4 to neutralise it Molecular weight H2SO4 = 2+32+64 = 98 so we need 9.8g – which I suppose should be rounded up to 10g (No need to be more precise on the molecular weights since the mass of NaOH is only shown to the nearest whole gram)
How many grams of NaOH are required to neutralize diprotic sulphuric acid?
Sign up for Ahrefs Webmaster Tools. Mass of 0.2 mol NaOH = 0.2 mol* 40g/mol = 8g NaOH required. 100mL of molar sulphuric acid is a tenth of a mole, so you need two tenths of a mole of sodium hydroxide to neutralise a tenth mole of diprotic sulphuric acid. Since the molecular mass of sodium hydroxide is 40 you need 8 grams.
How do you convert 8g of NaOH to moles?
This can be done with a periodic table. Then, divide your 8 grams by the mass of one mole of NaOH. The result is how much NaOH you have in moles. The final step is to divide this value by 2 (you only need half as much sulfuric acid) to get the quantity of H₂SO₄, in moles, required to neutralize the sodium hydroxide.