Table of Contents
- 1 How many even numbers greater than 300 can be formed?
- 2 What is total number of 3 digit odd numbers greater than 300?
- 3 How many numbers consisting of three different numbers and less than 300 which are formed from the numbers 0 1 2 3 and 4?
- 4 How many even numbers greater than 300 can you find?
- 5 How many 3 digit even numbers are possible at units place?
- 6 How many 4 digit numbers are there greater than 3000?
How many even numbers greater than 300 can be formed?
111 even numbers greater than 300 can be formed with the digits 1,2,3,4,5 if repetition of digits in a number is not allowed.
What is total number of 3 digit odd numbers greater than 300?
For the three digit number to be even the units digit can be any of the 0, or 2, or 4 ie in three ways. So total number of 3-digit even numbers greater than 300 = 3 × 6 × 3 = 54.
How many numbers consisting of three different numbers and less than 300 which are formed from the numbers 0 1 2 3 and 4?
The answer is 12.
How many 3 digit numbers greater than 600 can be formed?
so total numbers which is greater than 600 are = 2*3*6 = 36.
How many 3-digit codes can be generated using only even numbers?
For each of these ways, y can be chosen in 8 ways. Hence, the desired number is 41 × 8 = 328 numbers 3-digit even numbers exist with no repetitions. Units digit can be among 0,2,4,6,8. There are some good answers here.
How many even numbers greater than 300 can you find?
Find all even numbers greater than 300 using digits 1, 2, 3, 4, 5 without repetition. There are 111 such numbers. Good luck! 8 clever moves when you have $1,000 in the bank.
How many 3 digit even numbers are possible at units place?
Let the 3 digit even number be Only 3 numbers are possible at units place (2 , 4 & 6) as we need even number. Number of 3 digit even numbers = 3 × 5 × 4 = 60
How many 4 digit numbers are there greater than 3000?
Four-digit numbers greater than 3000 must have one of three digits (3 or 4 or 5) as its first digit. The next three digits must be selected from the four remaining digits available, so the number of permutations is: 4 * 3 * 2 = 24. There are 3 * 24 = 72 numbers of the form 3xxx, 4xxx, 5xxx (all of which are greater than 3000).
How many 3 digit numbers are there in 12+3?
So if the first digit is 3 or 5, the last digit can be 2 or 4, and the 2nd digit can be any of the 3 remaining digits: 2*2*3=12. If the first digit is 4, then the last digit has to be 2, and the 2nd can be any of the 3 remaining: 1*1*3=3. 12+3=15 total such 3-digit numbers. 4-digit numbers: The last digit has to be 2 or 4.