Table of Contents
How long does it take to accelerate to light speed?
It would take 353,7 days of constant 1G (9,81 m/s^2) acceleration to reach the speed of light. In that time you would travel 4,58 billion Km. You can’t reach the speed of light.
How fast is accelerating at 1g?
1 G is equivalent to an acceleration of 9.8 m/s and the speed of light is approximately 3 x 10^8 m/s sooo starting from an initial velocity (v_0) of 0 m/s we have.
How long does it take to get to Mars at 1g?
Suppose you could travel to Mars accelerating at 1 g for the first half the trip, then decelerating at 1 g for the final half of the trip. Along the way you’d feel a force equal to the force of gravity you’re used to, and you’d get there quickly. How quickly? According to the show, just three days.
How long does it take to reach 10\% the speed of light?
The speed of light in miles per hour = 6.706 x 10^8 mph = 67,060,000,000 mph or around 67 million miles per hour. From these numbers, I calculated almost 10 years to reach 10\% the speed of light. You say “the velocity V will be 21.8 mph. After 2 seconds, V= 21.8 x 2 = 43.6 mph and so on.” but is the third value additive or exponential?
How long would it take Han Solo to reach the speed of light?
For Han to take off from Mos Eisley and accelerate at 3 g ‘s to half the speed of light would take him two and a half months—hardly the makings of an exciting movie. Even at 9 g ‘s, it would take him nineteen days to reach half the speed of light, though he’d be dead long before the ship reached that speed.
Why can’t a large object reach the speed of light?
Larger masses are larger amounts of bound energy, and can NEVER reach the speed of light, at any acceleration.
What is the speed of light and acceleration of gravity?
In this case since the object’s initial velocity, final velocity, and acceleration is given we use the formula: a=Δv/Δt. ( speed of light is 3×10^(8) and acceleration of gravity or G is 9.8m/s^2. a=(vf-vi)/t , a=(3×10^(8)-0)/t , 9.8t=3×10^(8), t=30612244.9 seconds or 354.31 days.