What is the probability of taking out red marbles?
Correct answer: Note that there are 16 total marbles. A is simply a set of sequential events. On the first, you have 10/16 chances to draw a red. Supposing this red is not replaced, the chance of drawing a second red will be 9/15; therefore, the probability of A is (10/16) * (9/15) = 0.375.
What is the probability of pulling a red marble first without replacing the red marble pulling a blue marble second?
The probability of the first marble being red is 943. After returning this marble to the bag, the probability of the second marble being blue is 1143. So the probability picking a red marble, and then a blue marble is 943⋅1143≈0.054.
What is the probability of getting a red marble?
There are 18 marbles, of which 8 are blue and 6 are red . The probability of getting a blue marble is 8/18 or 4/9. The probability of getting a red marble is 6/18 or 1/3.
How many marbles are in a bag of marbles?
A bag contains 7 red marbles, 6 white marbles, and 10 blue marbles. You draw 4 marbles out at random, without replacement. What is the probability that all the marbles are red? What is the probability that exactly two of the marbles are red? What is the probability that none of the marbles are red? = C (16,4) / C (23,4) =
What is the probability of drawing a red on the first?
On the first, you have 10/16 chances to draw a red. Supposing this red is not replaced, the chance of drawing a second red will be 9/15; therefore, the probability of A is (10/16) * (9/15) = 0.375. Event B is translated into 2 events: Blue + (White or Red) or (White or Red) + Blue.
What are the odds of drawing a red ball in chess?
There is an 8/18 chance of drawing a blue ball and since you replaced it a And then 6/18 chance of drawing the red ball. When you multiply the fractions together and then reduce them you arrive with a 4/27 of a chance. , Just interested in math is all.