Table of Contents
- 1 How many gametes are required to produce 80 seeds in flowering plants?
- 2 How many meiosis are required for the formation of 80 male gametes in a typical flowering plant?
- 3 How many gametes are required to form a seed?
- 4 How many gametes will be required to form 100 seeds in Angiospermic plants?
- 5 How many meiotic divisions are required for 76 seeds?
- 6 How many meiosis are required for the formation of 50 embryo sac?
- 7 How many gametes are required for the formation of 400 seeds?
- 8 How many seeds are produced from one egg in meiosis?
How many gametes are required to produce 80 seeds in flowering plants?
In this plant 80 grains (seeds) are produced by fertilization between 80 male and 80 female gametes.
How many meiosis are required for the formation of 80 male gametes in a typical flowering plant?
1 meiosis produces 4 male gametes . So for 80 male gametes ,20 times meiosis is required .
How many meiosis does it take for 100 seeds?
One meiotic division in a pollen mother cell gives rise to 4 microspores, which develop into 4 pollen grains, therefore 25 meiotic divisions are required to produce 100 pollen grains.
How many meiotic divisions are necessary for forming 80 sperms?
Answer: The number of ‘meiotic divisions’ that are necessary for the production of 80 sperms is 20.
How many gametes are required to form a seed?
The angiosperm male gametophyte is composed of one tube cell and one generative cell. To form two male gametes, this generative cell divides. Thus the male gametophyte angiosperm is 3-celled.
How many gametes will be required to form 100 seeds in Angiospermic plants?
For formation of 100 zygotes, 100 male gametes and 100 female gametes (eggs) are required.
How many Microspore mother cell is the responsible for the formation of 80 Microspores in angiosperms?
So, 20 microspore mother cells are required to produce 80 male gametes in angiosperms.
How many mitosis and meiosis are required for formation of 100 brinjal seeds?
So, for the development of 100 microspores 100 meiotic division is required. – The megaspore (ovule) is also developed by the meiotic division. For the development of one megaspore one meiotic division is required.
How many meiotic divisions are required for 76 seeds?
95 meiotic divisions will be required to produce 76 seeds in Guava fruit. Explanation: In angiosperm megaspore contains mother cell. Number of seeds=76.
How many meiosis are required for the formation of 50 embryo sac?
Thus the correct answer is option ‘A’ which is 63 meiotic divisions.
How many meiotic divisions are required for 76 seeds in a guava fruit?
95 meiotic divisions will be required to produce 76 seeds in Guava fruit. Explanation: In angiosperm megaspore contains mother cell.
How many cells are required to form 80 seeds in dicotyledous plant?
Any one cell dividing by meiosis can produce only 4 daughter cells. So to make 80 seeds would require meiosis in a minimum of 20 cells. Originally Answered: How many meiosis are required to form 80 seeds in dicotyledous plant?
How many gametes are required for the formation of 400 seeds?
For the formation of 400 seeds in the pea plant, we require 400 male and 400 female gametes. In one meiotic division, one microspore mother cell in the anther forms 4 microspores, each of which develops as a pollen grain. For the production of 400 male gametes, the number of meiotic division is 400/4= 100.
How many seeds are produced from one egg in meiosis?
One egg is produced by the meiosis of egg mother cell. So, the total number of seeds is equal to the number of meiotic divisions in the female. It is also known that each pollen mother cells divide by meiosis to form four haploid pollen grains.
How many gametes are required for meiosis to occur?
During sexual reproduction in angiosperms, meiosis occurs in microspore and megaspore mother cells. For the formation of 400 seeds in the pea plant, we require 400 male and 400 female gametes. In one meiotic division, one microspore mother cell in the anther forms 4 microspores, each of which develops as a pollen grain.