Table of Contents
- 1 How do you prepare an aqueous solution of 30gm w/v NaOH?
- 2 What will be the molarity M of 20\% w/w NaOH solution if density of solution is 1.2g mL?
- 3 What is the molarity of 20 W v NaOH solution?
- 4 What is the density of NaOH?
- 5 What is the molarity of 20?
- 6 What is the molarity of 40 NaOH?
- 7 What is the density of a 3m solution of NaCl?
- 8 How do you find the molarity of a solution of NaOH?
- 9 How to calculate molarity and density of HCl solution?
How do you prepare an aqueous solution of 30gm w/v NaOH?
- Answer: mass fraction of water = 0.8.
- Explanation: 20\%(w/w) of NaOH :- 20 g NaOH in 100g solution. 30\%(w/v) of NaOH :- 30gm in 100ml of Solution. W of NaOH in 30 mL solution = (30/100)*30 g = 9g. Vol. of solution for 20g NaOH = (100/30)*20 mL = 200/3 mL. now,
- Mass Fraction of Water = 36/45 = 0.8.
What will be the molarity M of 20\% w/w NaOH solution if density of solution is 1.2g mL?
⇒ Molarity = 6 M.
What is the molarity of 20 W v NaOH solution?
20 gr of NaOH correspond to 0.5 moles which are contained in 0.5 liter of solution. In one liter of solution there will be (2)(0.5) = 1 mole and thus the solution is 1 M.
What will be the mole fraction of NaOH on a solution containing 30\% of NaOH by mass?
Mole fraction of NaOH will be 0.75/4.64= 0.1616.
What is the molarity of 30\% NaOH?
7.5 M
In the question, we have been given that $NaOH$ is present in 30 percent weight by volume. So, if we take a solution, weighing 100 grams, the amount of $NaOH$ that will be present in it should correspond to 30 grams. On solving, we get the final molarity as 7.5 M.
What is the density of NaOH?
2.13 g/cm³
Sodium hydroxide/Density
What is the molarity of 20?
20\% (w/v) means 20 g of H2SO4 is present in 100 mL (= 0.1L) of solution. M = 0.204 moles/0.1 L = 0.204 M.
What is the molarity of 40 NaOH?
Molarity of 40\% NaOH (w/w) solution is 12M.
What is the mole fraction of a solute in an aqueous solution of 30\% NaOH?
Mole fraction of solute in aqueous solution of 30\% NaOH. Mole fraction of NaOH in an aqueous solution is 0.3.
What is the density of 30\% NaOH solution?
An aqueous solution labelled 30\% (w/v) NaOH had a density of 1.20g/ml. What is the molality of the solution? – Quora An aqueous solution labelled 30\% (w/v) NaOH had a density of 1.20g/ml.
What is the density of a 3m solution of NaCl?
The density of a 3M solution of NaCl is 1.25g/ml. Calculate the molality of the solution. 3 Molar solution means there are 3 moles of NaCl salt in 1 Liter. Molecular weight of NaCl = 58.44. Hence, there are 3×58.44 gms in 1 Litre of water. So 1,074.68 ml or 1, 074.68 gms of water is mixed with 3 moles of Na Cl to make the 3 M solution.
How do you find the molarity of a solution of NaOH?
To get the molarity, you divide the moles of solute by the litres of solution. “Molarity” = “moles of solute”/”litres of solution” For example, a 0.25 mol/L NaOH solution contains 0.25 mol of sodium hydroxide in every litre of solution.
How to calculate molarity and density of HCl solution?
Solution Path #1: 1) Determine moles of HCl in 100.0 g of 37.7\% solution: 37.7 g of this solution is HCl 37.7 g / 36.4609 g/mol = 1.03398435 mol 2) Determine volume of 100.0 g of solution: density = mass / volume 1.19 g/mL = 100.0 g / x x = 84.0336 mL 3) Determine molarity: 1.03398435 mol / 0.0840336 L = 12.3 M Solution Path #2: