Table of Contents
- 1 What is the least natural number which leaves no remainder when divided by all the digits from 1to 9?
- 2 Which is the least natural number?
- 3 What is the least number when divided by 8 12 and 16 leaves 3 as remainder in each case but divided by 7 leaves no remainder?
- 4 How do you find the remainder when dividing by 10?
- 5 Which number has a remainder of 25 when divided by 35?
- 6 What is the remainder when 599 is divided by 9?
What is the least natural number which leaves no remainder when divided by all the digits from 1to 9?
Solution(By Examveda Team) The least natural number which leaves no remainder when divided by all the digit from 1 to 9 should be the LCM of 1 to 9.
Which is the least natural number?
1
The smallest natural number is 1. The smallest whole number is 0.
Which is the smallest whole number and natural number?
0 is the smallest whole number. 1 is the smallest natural number.
What is the least number when divided by 8 12 and 16 leaves 3 as remainder in each case but divided by 7 leaves no remainder?
So the ans. is 147.
How do you find the remainder when dividing by 10?
First, if a number is being divided by 10, then the remainder is just the last digit of that number. Similarly, if a number is being divided by 9, add each of the digits to each other until you are left with one number (e.g., 1164 becomes 12 which in turn becomes 3), which is the remainder.
What is the remainder when 821 is divided by 4?
There are 3 ways of writing a remainder: with an R, as a fraction, and as a decimal. For example, 821 divided by 4 would be written as 205 R 1 in the first case, 205 1 / 4 in the second, and 205.25 in the third. What is the remainder when 26 is divided by 6?
Which number has a remainder of 25 when divided by 35?
Find the least number which when divided by 15, leaves a remainder of 5, when divided by 25, leaves a remainder of 15 and when divided by 35 leaves a remainder of 25. Now, number has a remainder of 25 when divided by 35. Similarly, number has remainder 15 on dividing by 25 and remainder is 5 when divided by 15.
What is the remainder when 599 is divided by 9?
What is the remainder when 599 is divided by 9? The remainder is 5 . To calculate this, first divide 599 by 9 to get the largest multiple of 9 before 599. 5/9 < 1, so carry the 5 to the tens, 59/9 = 6 r 5, so carry the 5 to the digits. 59/9 = 6 r 5 again, so the largest multiple is 66.