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What is the average of all numbers between 100 and 200 which is divisible by 13?
What is the average of all numbers between 100 and 200 which are divisible by 13? There are 8 numbers present between 100 and 200 that are divisible by 13 ,and those are : 104,117,…,182,195. So,total of them=(8/2)(104+195)=1196. So, average of them=1196/8=149.5.
How many numbers between 100 and 300 which are divisible by 13?
Here, between 100 and 300, the first number which divisible by 13 is 104 and the last number which is divisible by 13 is 299, and the common difference is 13. Therefore, there are 16 numbers between 100 and 300 which are divisible by 13.
How many whole numbers are there between 100 and 200?
there are 99 whole number in between 100 and 200.
How many numbers are there between 200 and 500 which are divisible by 13?
208 221 234 247 260 273 286 299 312 325 338 351 364 377 390 403 416 429 442 455 468 481 494 are all divisible by 13. In a more simplified version- there are 23 numbers between 200 and 500 that are divisible by 13.
How many even numbers are there from 1 to 200?
Solution: We know that, from 1 to 200, there are 100 even numbers. Thus, n =100 By the formula of the sum of even numbers we know; S n = n (n+1)
How do you find the sum of even and odd numbers?
Also, find sum of odd numbers here. Basically, the formula to find the sum of even numbers is n (n+1), where n is the natural number. We can find this formula using the formula of the sum of natural numbers, such as: S = 1 + 2+3+4+5+6+7…+n. S= n (n+1)/2.
What is the sum of first ten even numbers?
Sum of First Ten Even numbers Number of consecutive even numbers (n) Sum of even numbers (Sn = n (n+1)) Recheck 1 1 (1+1)=1×2=2 2 2 2 (2+1) = 2×3 = 6 2+4 = 6 3 3 (3+1)=3×4 = 12 2+4+6 = 12 4 4 (4+1) = 4 x 5 = 20 2+4+6+8=20
How do you find the sum of consecutive even numbers?
Basically, the formula to find the sum of even numbers is n(n+1), where n is the natural number. We can find this formula using the formula of the sum of natural numbers, such as: S = 1 + 2+3+4+5+6+7…+n. S= n(n+1)/2. To find the sum of consecutive even numbers, we need to multiply the above formula by 2. Hence, S e = n(n+1)